63=2x^2+11x

Solution for 63=2x^2+11x equation:

63=2x^2+11x

We move all terms to the left:

63-(2x^2+11x)=0

We get rid of parentheses

-2x^2-11x+63=0

a = -2; b = -11; c = +63;
Δ = b2-4ac
Δ = -112-4·(-2)·63
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-25}{2*-2}=\frac{-14}{-4}
=3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+25}{2*-2}=\frac{36}{-4}
=-9
$